In the charging of a capacitor,what is the contradiction in Ampere's circuital law?

$A$ parallel plate capacitor is completely immersed in a liquid of resistivity $\rho = 0.25 \, \Omega m$ and relative permittivity $\epsilon_r = 80$. If the plates of the capacitor are connected to an alternating voltage source of $V = V_0 \sin(\omega t)$ at a frequency of $f = 0.4 \, GHz$,then the ratio of the amplitudes of the displacement current $(I_d)$ and conduction current $(I_c)$ is:

If the rate of change in electric flux between the plates of a capacitor is $9 \pi \times 10^3 \text{ Vm s}^{-1}$,then the displacement current inside the capacitor is (in $\mu \text{A}$)

What suggestion was made to correct the discrepancies in Ampere's circuital law?

Seawater at a frequency $f = 9 \times 10^{2} \, Hz$ has permittivity $\varepsilon = 80 \varepsilon_{0}$ and resistivity $\rho = 0.25 \, \Omega m$. Imagine a parallel plate capacitor is immersed in seawater and is driven by an alternating voltage source $V(t) = V_{0} \sin(2 \pi ft)$. Then the conduction current density becomes $10^{x}$ times the displacement current density after time $t = \frac{1}{800} \, s$. The value of $x$ is ......... . $\left(\frac{1}{4 \pi \varepsilon_{0}} = 9 \times 10^{9} \, Nm^{2} C^{-2}\right)$

You are given a $2 \,\mu F$ parallel plate capacitor. How would you establish an instantaneous displacement current of $1 \, mA$ in the space between its plates?